Integrand size = 26, antiderivative size = 115 \[ \int \sec (c+d x) (a \sin (c+d x)+b \tan (c+d x))^3 \, dx=\frac {3 a^2 b \cos (c+d x)}{d}+\frac {a^3 \cos ^2(c+d x)}{2 d}-\frac {a \left (a^2-3 b^2\right ) \log (\cos (c+d x))}{d}+\frac {b \left (3 a^2-b^2\right ) \sec (c+d x)}{d}+\frac {3 a b^2 \sec ^2(c+d x)}{2 d}+\frac {b^3 \sec ^3(c+d x)}{3 d} \]
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Time = 0.28 (sec) , antiderivative size = 115, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {4482, 2916, 12, 908} \[ \int \sec (c+d x) (a \sin (c+d x)+b \tan (c+d x))^3 \, dx=\frac {a^3 \cos ^2(c+d x)}{2 d}+\frac {b \left (3 a^2-b^2\right ) \sec (c+d x)}{d}-\frac {a \left (a^2-3 b^2\right ) \log (\cos (c+d x))}{d}+\frac {3 a^2 b \cos (c+d x)}{d}+\frac {3 a b^2 \sec ^2(c+d x)}{2 d}+\frac {b^3 \sec ^3(c+d x)}{3 d} \]
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Rule 12
Rule 908
Rule 2916
Rule 4482
Rubi steps \begin{align*} \text {integral}& = \int (b+a \cos (c+d x))^3 \sec (c+d x) \tan ^3(c+d x) \, dx \\ & = -\frac {\text {Subst}\left (\int \frac {a^4 (b+x)^3 \left (a^2-x^2\right )}{x^4} \, dx,x,a \cos (c+d x)\right )}{a^3 d} \\ & = -\frac {a \text {Subst}\left (\int \frac {(b+x)^3 \left (a^2-x^2\right )}{x^4} \, dx,x,a \cos (c+d x)\right )}{d} \\ & = -\frac {a \text {Subst}\left (\int \left (-3 b+\frac {a^2 b^3}{x^4}+\frac {3 a^2 b^2}{x^3}+\frac {3 a^2 b-b^3}{x^2}+\frac {a^2-3 b^2}{x}-x\right ) \, dx,x,a \cos (c+d x)\right )}{d} \\ & = \frac {3 a^2 b \cos (c+d x)}{d}+\frac {a^3 \cos ^2(c+d x)}{2 d}-\frac {a \left (a^2-3 b^2\right ) \log (\cos (c+d x))}{d}+\frac {b \left (3 a^2-b^2\right ) \sec (c+d x)}{d}+\frac {3 a b^2 \sec ^2(c+d x)}{2 d}+\frac {b^3 \sec ^3(c+d x)}{3 d} \\ \end{align*}
Time = 1.40 (sec) , antiderivative size = 100, normalized size of antiderivative = 0.87 \[ \int \sec (c+d x) (a \sin (c+d x)+b \tan (c+d x))^3 \, dx=\frac {36 a^2 b \cos (c+d x)+3 a^3 \cos (2 (c+d x))+2 \left (-6 a \left (a^2-3 b^2\right ) \log (\cos (c+d x))-6 b \left (-3 a^2+b^2\right ) \sec (c+d x)+9 a b^2 \sec ^2(c+d x)+2 b^3 \sec ^3(c+d x)\right )}{12 d} \]
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Time = 8.56 (sec) , antiderivative size = 101, normalized size of antiderivative = 0.88
method | result | size |
derivativedivides | \(\frac {\frac {b^{3} \sec \left (d x +c \right )^{3}}{3}+\frac {3 a \,b^{2} \sec \left (d x +c \right )^{2}}{2}+3 a^{2} b \sec \left (d x +c \right )-\sec \left (d x +c \right ) b^{3}+\frac {3 a^{2} b}{\sec \left (d x +c \right )}+\frac {a^{3}}{2 \sec \left (d x +c \right )^{2}}+a \left (a^{2}-3 b^{2}\right ) \ln \left (\sec \left (d x +c \right )\right )}{d}\) | \(101\) |
default | \(\frac {\frac {b^{3} \sec \left (d x +c \right )^{3}}{3}+\frac {3 a \,b^{2} \sec \left (d x +c \right )^{2}}{2}+3 a^{2} b \sec \left (d x +c \right )-\sec \left (d x +c \right ) b^{3}+\frac {3 a^{2} b}{\sec \left (d x +c \right )}+\frac {a^{3}}{2 \sec \left (d x +c \right )^{2}}+a \left (a^{2}-3 b^{2}\right ) \ln \left (\sec \left (d x +c \right )\right )}{d}\) | \(101\) |
risch | \(i a^{3} x -3 i x a \,b^{2}+\frac {a^{3} {\mathrm e}^{2 i \left (d x +c \right )}}{8 d}+\frac {3 b \,{\mathrm e}^{i \left (d x +c \right )} a^{2}}{2 d}+\frac {3 b \,{\mathrm e}^{-i \left (d x +c \right )} a^{2}}{2 d}+\frac {a^{3} {\mathrm e}^{-2 i \left (d x +c \right )}}{8 d}+\frac {2 i a^{3} c}{d}-\frac {6 i a \,b^{2} c}{d}+\frac {2 b \left (9 a^{2} {\mathrm e}^{5 i \left (d x +c \right )}-3 b^{2} {\mathrm e}^{5 i \left (d x +c \right )}+9 a b \,{\mathrm e}^{4 i \left (d x +c \right )}+18 a^{2} {\mathrm e}^{3 i \left (d x +c \right )}-2 b^{2} {\mathrm e}^{3 i \left (d x +c \right )}+9 a b \,{\mathrm e}^{2 i \left (d x +c \right )}+9 a^{2} {\mathrm e}^{i \left (d x +c \right )}-3 b^{2} {\mathrm e}^{i \left (d x +c \right )}\right )}{3 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{3}}-\frac {a^{3} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{d}+\frac {3 a \,b^{2} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{d}\) | \(279\) |
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Time = 0.26 (sec) , antiderivative size = 122, normalized size of antiderivative = 1.06 \[ \int \sec (c+d x) (a \sin (c+d x)+b \tan (c+d x))^3 \, dx=\frac {6 \, a^{3} \cos \left (d x + c\right )^{5} + 36 \, a^{2} b \cos \left (d x + c\right )^{4} - 3 \, a^{3} \cos \left (d x + c\right )^{3} - 12 \, {\left (a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{3} \log \left (-\cos \left (d x + c\right )\right ) + 18 \, a b^{2} \cos \left (d x + c\right ) + 4 \, b^{3} + 12 \, {\left (3 \, a^{2} b - b^{3}\right )} \cos \left (d x + c\right )^{2}}{12 \, d \cos \left (d x + c\right )^{3}} \]
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\[ \int \sec (c+d x) (a \sin (c+d x)+b \tan (c+d x))^3 \, dx=\int \left (a \sin {\left (c + d x \right )} + b \tan {\left (c + d x \right )}\right )^{3} \sec {\left (c + d x \right )}\, dx \]
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Time = 0.22 (sec) , antiderivative size = 109, normalized size of antiderivative = 0.95 \[ \int \sec (c+d x) (a \sin (c+d x)+b \tan (c+d x))^3 \, dx=-\frac {3 \, {\left (\sin \left (d x + c\right )^{2} + \log \left (\sin \left (d x + c\right )^{2} - 1\right )\right )} a^{3} + 9 \, a b^{2} {\left (\frac {1}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right )^{2} - 1\right )\right )} - 18 \, a^{2} b {\left (\frac {1}{\cos \left (d x + c\right )} + \cos \left (d x + c\right )\right )} + \frac {2 \, {\left (3 \, \cos \left (d x + c\right )^{2} - 1\right )} b^{3}}{\cos \left (d x + c\right )^{3}}}{6 \, d} \]
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Exception generated. \[ \int \sec (c+d x) (a \sin (c+d x)+b \tan (c+d x))^3 \, dx=\text {Exception raised: TypeError} \]
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Time = 26.18 (sec) , antiderivative size = 219, normalized size of antiderivative = 1.90 \[ \int \sec (c+d x) (a \sin (c+d x)+b \tan (c+d x))^3 \, dx=\frac {2\,a^3\,\mathrm {atanh}\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\right )-6\,a\,b^2\,\mathrm {atanh}\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\right )}{d}-\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (-2\,a^3-12\,a^2\,b+6\,a\,b^2+\frac {4\,b^3}{3}\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,\left (6\,a^3-12\,a^2\,b+6\,a\,b^2-4\,b^3\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (6\,a^3-12\,a^2\,b+6\,a\,b^2+\frac {20\,b^3}{3}\right )+12\,a^2\,b-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8\,\left (6\,a\,b^2-2\,a^3\right )-\frac {4\,b^3}{3}}{d\,{\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2-1\right )}^3\,{\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}^2} \]
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